JEE Mains · Maths · STD 11 - 9. straight line
If the line \(3x + 4y -24 = 0\) intersects the \(x-\) axis at the point \(A\) and the \(y-\) axis at the point \(B\), then the incentre of the triangle \(OAB\), where \(O\) is the origin, is
- A \((3, 4)\)
- B \((2, 2)\)
- C \((4, 3)\)
- D \((4, 4)\)
Answer & Solution
Correct Answer
(B) \((2, 2)\)
Step-by-step Solution
Detailed explanation
\(I = \left( {\frac{{a{x_1} + b{x_2} + c{x_3}}}{{a + b + c}},\frac{{a{y_1} + b{y_2} + c{y_3}}}{{a + b + c}}} \right)\)…
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