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JEE Mains · Maths · STD 11 - 6. permutation and combination

There are \(4\) men and \(5\) women in Group \(A\), and \(5\) men and \(4\) women in Group \(B.\) If \(4\) persons are selected from each group, then the number of ways of selecting \(4\) men and \(4\) women is ....................

  1. A \(9856\)
  2. B \(5626\)
  3. C \(4521\)
  4. D \(3574\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(5626\)

Step-by-step Solution

Detailed explanation

From Group \(A\) From Group \(B\) Ways of selection \(4M\) \(4W\) \({ }^4 \mathrm{C}_4{ }^4 \mathrm{C}_4=1\) \(3M\ \ 2W\) \(1M\ \ 3W\) \({ }^4 \mathrm{C}_3{ }^5 \mathrm{C}_1{ }^5 \mathrm{C}_1{ }^4 \mathrm{C}_3=400\) \(2M\ \ 2W\) \(2M\ \ 2W\)…
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