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JEE Mains · Maths · STD 11 - 10.1 circle and system of circle

If the curve \(x^{2}+2 y^{2}=2\) intersects the line \(x + y =1\) at two points \(P\) and \(Q ,\) then the angle subtended by the line segment \(PQ\) at the origin is ...... .

  1. A \(\frac{\pi}{2}+\tan ^{-1}\left(\frac{1}{3}\right)\)
  2. B \(\frac{\pi}{2}-\tan ^{-1}\left(\frac{1}{3}\right)\)
  3. C \(\frac{\pi}{2}-\tan ^{-1}\left(\frac{1}{4}\right)\)
  4. D \(\frac{\pi}{2}+\tan ^{-1}\left(\frac{1}{4}\right)\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\frac{\pi}{2}+\tan ^{-1}\left(\frac{1}{4}\right)\)

Step-by-step Solution

Detailed explanation

Homogenising \(x^{2}+2 y^{2}-2(x+y)^{2}=0\) \(\Rightarrow-x^{2}-4 x y=0 \Rightarrow x^{2}+4 x y=0\) Lines are \(x=0\) and \(y=-\frac{x}{4}\) Angle between lines \(=\frac{\pi}{2}+\tan ^{-1} \frac{1}{4}\)
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