JEE Mains · Maths · STD 12 - 11. three dimension geometry
Let the lines \(\frac{x-1}{\lambda}=\frac{y-2}{1}=\frac{z-3}{2}\) and \(\frac{ x +26}{-2}=\frac{ y +18}{3}=\frac{ z +28}{\lambda}\) be coplanar and \(P\) be the plane containing these two lines. Then which of the following points does \(NOT\) lies on \(P\)?
- A \((0,-2,-2)\)
- B \((-5,0,-1)\)
- C \((3,-1,0)\)
- D \((0,4,5)\)
Answer & Solution
Correct Answer
(D) \((0,4,5)\)
Step-by-step Solution
Detailed explanation
Given, \(L_{1}: \frac{x-1}{\lambda}=\frac{y-2}{1}=\frac{z-3}{2}\) and \(L_{2}: \frac{x+26}{-2}=\frac{y+18}{3}=\frac{z+28}{\lambda}\) are coplanar…
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