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JEE Mains · Maths · STD 12 - 5. continuity and differentiation

The value of \(k\) for which the function \(f\left( x \right) = \left\{ \begin{gathered} {\left( {\frac{4}{5}} \right)^{\frac{{\tan \,4x}}{{\tan \,5x}}}},\,\,\,\,0 < x < \frac{\pi }{2} \hfill \\  k + \frac{2}{5}\,\,\,,\,\,\,\,\,\,\,\,\,\,\,x = \frac{\pi }{2} \hfill \\ \end{gathered}  \right.\) is continuous at  \(x\,= \frac{\pi}{2}\) is

  1. A \(\frac{17}{20}\)
  2. B \(\frac{2}{5}\)
  3. C \(\frac{3}{5}\)
  4. D \(-\frac{2}{5}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac{3}{5}\)

Step-by-step Solution

Detailed explanation

\(\mathop {\lim }\limits_{x \to \pi /2} f\left( x \right) = f\left( {\pi /2} \right)\) \(k + 2/5 = 1\) \(k = 1 - \frac{2}{5}\) \(k = \frac{3}{5}\)