JEE Mains · Maths · STD 11 - 7. binomial theoram
The coefficient of \(x^{2012}\) in the expansion of \((1-x)^{2008}\left(1+x+x^2\right)^{2007}\) is equal to
- A \(0\)
- B \(11\)
- C \(2\)
- D \(3\)
Answer & Solution
Correct Answer
(A) \(0\)
Step-by-step Solution
Detailed explanation
\( (1-x)(1-x)^{2007}\left(1+x+x^2\right)^{2007} \) \( (1-x)\left(1-x^3\right)^{2007} \) \( (1-x)\left({ }^{2007} C_0-{ }^{2007} C_1\left(x^3\right)+\ldots \ldots .\right)\) General term \( (1-x)\left((-1)^r{ }^{2007} C_r x^{3 r}\right) \)…
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