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JEE Mains · Maths · STD 11 - 8. sequence and series
The value of \({1^2} + {3^2} + {5^2} + ....... + {25^2}\) is
- A \(2925\)
- B \(1469\)
- C \(1728\)
- D \(1456\)
Answer & Solution
Correct Answer
(A) \(2925\)
Step-by-step Solution
Detailed explanation
Consider \({1^2} + {3^2} + {5^2} + .... + {25^2}\) \({n^{th}}\) term \({T_n} = {\left( {2n - 1} \right)^2},n = 1,.....13\) Now, \({S_n} = \,\sum\limits_{n = 1}^{13} {{T_n} = } \sum\limits_{n = 1}^{13} {{{\left( {2n - 1} \right)}^2}} \)…
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