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JEE Mains · Maths · STD 12 - 1. relation and function

Let \(f(\mathrm{x})=\left\{\begin{array}{cl}-\mathrm{a} & \text { if }-\mathrm{a} \leq \mathrm{x} \leq 0 \\ \mathrm{x}+\mathrm{a} & \text { if } 0<\mathrm{x} \leq \mathrm{a}\end{array}\right.\) where \(\mathrm{a}>0\) and \(\mathrm{g}(\mathrm{x})=(f|\mathrm{x}|)-|f(\mathrm{x})|) / 2\).  Then the function \(\mathrm{g}:[-\mathrm{a}, \mathrm{a}] \rightarrow[-\mathrm{a}, \mathrm{a}]\) is

  1. A neither one-one nor onto.
  2. B both one-one and onto.
  3. C  one-one.
  4. D onto
Verified Solution

Answer & Solution

Correct Answer

(A) neither one-one nor onto.

Step-by-step Solution

Detailed explanation

\(y=f(x)\) \(y=f|x|\) \(y=|f(x)|\) \(g(x)=\frac{f(|x|)-|f(x)|}{2}\)
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