JEE Mains · Maths · STD 11 - 14. probability
If an unbiased dice is rolled thrice, then the probability of getting a greater number in the \(i^{\text {th }}\) roll than the number obtained in the \((i-1)^{\text {th }}\) roll, \(i=2,3\), is equal to :
- A \(3 / 54\)
- B \(2 / 54\)
- C \(5 / 54\)
- D \(1 / 54\)
Answer & Solution
Correct Answer
(C) \(5 / 54\)
Step-by-step Solution
Detailed explanation
Favourable cases \(={ }^6 \mathrm{C}_3\) Total out comes \(=6^3\) Probability of getting greater number than previous \(\text { one }=\frac{{ }^6 \mathrm{C}_3}{\mathrm{r}^3}=\frac{20}{216}=\frac{5}{54}\)
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