ExamBro
ExamBro
JEE Mains · Maths · STD 11 - 8. sequence and series

The sum of the first \(20\) terms of the series \(5+11+\) \(19+29+41+\ldots\) is \(..........\).

  1. A \(3450\)
  2. B \(3250\)
  3. C \(3420\)
  4. D \(3520\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(3520\)

Step-by-step Solution

Detailed explanation

\(S _{20}=5+11+19+29+\ldots \ldots\) Let \(T _{ r }=a r^2+ br + c\) \(T _1= a + b + c =5\) \(T _2=4 a +2 b + c =11\) \(T _3=9 a +3 b + c =19\) \(a =1, b =3, c =1\) Hence \(S _{20}=\sum_{ r =1}^{20} r ^2+3 \sum_{ r =1}^{20} r +\sum_{ r =1}^{20} 1=3520\)
Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app