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JEE Mains · Maths · STD 11 - 6. permutation and combination

Let \(x\) and \(y\) be distinct integers where \(1 \leq x \leq 25\) and \(1 \leq y \leq 25\). Then, the number of ways of choosing \(x\) and \(y\), such that \(x + y\) is divisible by \(5\) , is \(.........\).

  1. A \(119\)
  2. B \(120\)
  3. C \(118\)
  4. D \(117\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(120\)

Step-by-step Solution

Detailed explanation

\(x+y=5 \lambda\) Cases: \(x\) \(y\) Number of ways \(5 \lambda\) \(5 \lambda\) \(20\) \(5 \lambda+1\) \(5 \lambda+4\) \(25\) \(5 \lambda+2\) \(5 \lambda+3\) \(25\) \(5 \lambda+3\) \(5 \lambda+2\) \(25\) \(5 \lambda+4\) \(5 \lambda+1\) \(25\) Total=120
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