JEE Mains · Maths · STD 11 - 3. trignometrical ratios,functions and identities
In the figure, \(\theta_1+\theta_2=\frac{\pi}{2}\) and \(\sqrt{3}(B E)=4(A B)\). If the area of \(\triangle CAB\) is \(2 \sqrt{3}-3\) unit \(^2\), when \(\frac{\theta_2}{\theta_1}\) is the largest, then the perimeter (in unit) of \(\triangle CED\) is equal to \(...........\).
- A \(5\)
- B \(4\)
- C \(6\)
- D \(3\)
Answer & Solution
Correct Answer
(C) \(6\)
Step-by-step Solution
Detailed explanation
\(\sqrt{3} BE =4 AB\) \(Ar (\triangle CAB )=2 \sqrt{3}-3\) \(\frac{1}{2} x ^2 \tan \theta_1=2 \sqrt{3}-3\) \(BE = BD + DE\) \(= x \left(\tan \theta_1+\tan \theta_2\right)\) \(BE = AB \left(\tan \theta_1+\cot \theta_1\right)\)…
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