JEE Mains · Maths · STD 12 - 7.2 definite integral
The value of the integral \(\int\limits_{-2}^{2} \frac{\left|x^{3}+x\right|}{\left(e^{x|x|}+1\right)} d x\) is equal to
- A \(5 e^{2}\)
- B \(6\)
- C \(4\)
- D \(3 e ^{-2}\)
Answer & Solution
Correct Answer
(B) \(6\)
Step-by-step Solution
Detailed explanation
\(f(x)=\frac{\left|x^{3}+x\right|}{\left(e^{x|x|}+1\right)} d x\) \(\int\limits_{-2}^{2} f(x) d x=\int\limits_{0}^{2}(f(x)+f(-x)) d x\)…
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