JEE Mains · Maths · STD 11 - 10.1 circle and system of circle
Let the latus ractum of the parabola \(y ^{2}=4 x\) be the common chord to the circles \(C _{1}\) and \(C _{2}\) each of them having radius \(2 \sqrt{5}\). Then, the distance between the centres of the circles \(C _{1}\) and \(C _{2}\) is
- A \(8\)
- B \(4 \sqrt{5}\)
- C \(12\)
- D \(8 \sqrt{5}\)
Answer & Solution
Correct Answer
(A) \(8\)
Step-by-step Solution
Detailed explanation
Length of latus rectum \(=4\) \(DB =2\) \(C _{1} B =\sqrt{\left( C _{1} D \right)^{2}-( DB )^{2}}=4\) \(C _{1} C _{2}=8\)
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