JEE Mains · Maths · STD 11 - 11. introduction to three dimensional geometry
The square of the distance of the point of intersection of the lines \(\vec{r} = (\hat{i} + \hat{j} - \hat{k}) + \lambda(a\hat{i} - \hat{j})\), \(a \neq 0\) and \(\vec{r} = (4\hat{i} - \hat{k}) + \mu(2\hat{i} + a\hat{k})\) from the origin is:
- A \(5\)
- B \(10\)
- C \(17\)
- D \(26\)
Answer & Solution
Correct Answer
(C) \(17\)
Step-by-step Solution
Detailed explanation
Equating the position vectors of the two lines for intersection: \((1 + a\lambda)\hat{i} + (1 - \lambda)\hat{j} - \hat{k} = (4 + 2\mu)\hat{i} + 0\hat{j} + (-1 + a\mu)\hat{k}\) Comparing the coefficients of \(\hat{i}, \hat{j}, \hat{k}\):…
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