JEE Mains · Maths · STD 11 - 10.2 parabola,ellipse,hyperbola
The equation of a tangent to the hyperbola \(4x^2 -5y^2 = 20\) parallel to the line \(x -y = 2\) is
- A \(x -y + 1 = 0\)
- B \(x -y + 7 = 0\)
- C \(x -y + 9 = 0\)
- D \(x -y -3 = 0\)
Answer & Solution
Correct Answer
(A) \(x -y + 1 = 0\)
Step-by-step Solution
Detailed explanation
Hyperbola is \(\frac{{{x^2}}}{5} - \frac{{{y^2}}}{4} = 1\) Equation of its tangent in slop from is \(y = mx \pm \sqrt {5{m^2} - 4} \) Hence tangent with slope \(1\) is \(y = x \pm 1\)
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