JEE Mains · Maths · STD 12 - 10. vector algebra
The area (in sq. units) of the parallelogram whose diagonals are along the vectors \(8\hat i - 6\hat j\) and \(3\hat i + 4\hat j - 12\hat k\) , is
- A \(26\)
- B \(65\)
- C \(20\)
- D \(52\)
Answer & Solution
Correct Answer
(B) \(65\)
Step-by-step Solution
Detailed explanation
\(\text { Let; } d_{1}=8 \hat{i}-6 \hat{j}+0 \hat{k} \) and \(d_{2}=3 \hat{i}+4 \hat{j}-12 \hat{k}\)…
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