JEE Mains · Maths · STD 12 - 11. three dimension geometry
The direction ratios of normal to the plane through the points \((0, -1, 0)\) and \((0, 0, 1)\) and making an angle \(\frac {\pi }{4}\) with the plane \(y -z + 5 = 0\)
- A \(2, -1, 1\)
- B \(2, \sqrt 2, - \sqrt 2\)
- C \(\sqrt 2, 1, - 1\)
- D Both \((B)\) and \((C)\)
Answer & Solution
Correct Answer
(D) Both \((B)\) and \((C)\)
Step-by-step Solution
Detailed explanation
d. \(\mathrm{r},\) of \(\mathrm{AB}\) \(=(0,1,1)\) \(a \cdot 0+b \cdot 1+c \cdot 1=0\) \(b+c=0\) \(b+c=0\) ......\((i)\) \(\cos \frac{\pi}{4}=\frac{a \cdot 0+b(1)+c(-1)}{\sqrt{a^{2}+b^{2}+c^{2}} \cdot \sqrt{2}}\)…
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