ExamBro
ExamBro
JEE Mains · Maths · STD 12 - 10. vector algebra

The area of the quadrilateral \(ABCD\) with vertices \(A (2,1,1), B (1,2,5), C (-2,-3,5)\) and \(D (1,-6,-\) 7) is equal to

  1. A \(48\)
  2. B \(8 \sqrt{38}\)
  3. C \(54\)
  4. D \(9 \sqrt{38}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(8 \sqrt{38}\)

Step-by-step Solution

Detailed explanation

\(\text { Vector Area }=\overrightarrow{ v }\) \(=\frac{1}{2} \overrightarrow{ AB } \times \overrightarrow{ AC }+\frac{1}{2} \overrightarrow{ AC } \times \overrightarrow{ AD }\) \(=\frac{1}{2}(\overrightarrow{ AB }-\overrightarrow{ AD }) \times \overrightarrow{ AC }\)…
From JEE Mains
Explore more questions on app