JEE Mains · Maths · STD 12 - 6. Application of derivatives
The equation of the normal to the curve \(y=(1+x)^{2 y}+\cos ^{2}\left(\sin ^{-1} x\right)\) at \(x=0\) is
- A \(y=4 x+2\)
- B \(x+4 y=8\)
- C \(y+4 x=2\)
- D \(2 y+x=4\)
Answer & Solution
Correct Answer
(B) \(x+4 y=8\)
Step-by-step Solution
Detailed explanation
Given equation of curve \(y=(1+x)^{2 y}+\cos ^{2}\left(\sin ^{-1} x\right)\) at \(\sqrt{x=0}\) \(y=(1+0)^{2 y}+\cos ^{2}\left(\sin ^{-1} 0\right)\) \(y=1+1\) \(y=2\) So we have to find the normal at (0,2) Now…
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