JEE Mains · Maths · STD 11 - 6. permutation and combination
An urn contains \(5\) red marbles, \(4\) black marbles and \(3\) white marbles. Then the number of ways in which \(4\) marbles can be drawn so that at the most three of them are red is
- A \(540\)
- B \(450\)
- C \(420\)
- D \(490\)
Answer & Solution
Correct Answer
(D) \(490\)
Step-by-step Solution
Detailed explanation
The question does not mention that whether same coloured marbles are distinct or identical. So, assuming they are distinct our required answer \(=^{12} \mathrm{C}_{4}-^{5} \mathrm{C}_{4}=490\)
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