ExamBro
ExamBro
JEE Mains · Maths · STD 11 - 7. binomial theoram

The coefficient of \(x^{18}\) in the expansion of \(\left(x^4-\frac{1}{x^3}\right)^{15}\) is \(...........\).

  1. A \(5004\)
  2. B \(5003\)
  3. C \(5002\)
  4. D \(5005\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(5005\)

Step-by-step Solution

Detailed explanation

\(\left(x^4-\frac{1}{x^3}\right)^{15}\) \(T_{r+1}={ }^{15} C_r\left(x^4\right)^{15-r}\left(\frac{-1}{x^3}\right)^r\) \(60-7 r=18\) \(r=6\) Hence coeff. of \(x^{18}={ }^{15} C _6=5005\)
Same subject
Explore more questions on app