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JEE Mains · Maths · STD 12 - 7.2 definite integral

If \(f(t)=\int_0^\pi \frac{2 x d x}{1-\cos ^2 \sin ^2 x}, 0 < t < \pi\), then the value of \(\int_0^{\frac{\pi}{2}} \frac{\pi^2 d t}{f(t)}\) equals ..........

  1. A \(3\)
  2. B \(9\)
  3. C \(1\)
  4. D \(7\)
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Answer & Solution

Correct Answer

(C) \(1\)

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Detailed explanation

\(f(t)=\int_0^\pi \frac{2 x}{1-\cos ^2 t \sin ^2 x} d x\) ..................(\(1\)) \(=2 \int_0^\pi \frac{(\pi-x) d x}{1-\cos ^2 \sin ^2 x}\) ..................(\(2\)) \( 2 f(t)=2 \int_0^\pi \frac{\pi}{1-\cos ^2 t \sin ^2 x} d x \)…
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