JEE Mains · Maths · STD 12 - 1. relation and function
Let \(R =\{( P , Q ) \mid P\) and \(Q\) are at the same distance from the origin \(\}\) be a relation, then the equivalence class of \((1,-1)\) is the set
- A \(S =\left\{( x , y ) \mid x ^{2}+ y ^{2}=4\right\}\)
- B \(S =\left\{( x , y ) \mid x ^{2}+ y ^{2}=1\right\}\)
- C \(S =\left\{( x , y ) \mid x ^{2}+ y ^{2}=\sqrt{2}\right\}\)
- D \(S=\left\{(x, y) \mid x^{2}+y^{2}=2\right\}\)
Answer & Solution
Correct Answer
(D) \(S=\left\{(x, y) \mid x^{2}+y^{2}=2\right\}\)
Step-by-step Solution
Detailed explanation
Equivalence class of \((1,-1)\) is a circle with centre at \((0,0)\) and radius \(=\sqrt{2}\) \(\Rightarrow x^{2}+y^{2}=2\) \(S=\left\{(x, y) \mid x^{2}+y^{2}=2\right\}\)
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