JEE Mains · Maths · STD 11 - 7. binomial theoram
The term independent of \(x\) in the binomial expansion of \(\left( {1 - \frac{1}{x} + 3{x^5}} \right){\left( {2{x^2} - \frac{1}{x}} \right)^8}\) is
- A \(496\)
- B \(-496\)
- C \(400\)
- D \(-400\)
Answer & Solution
Correct Answer
(C) \(400\)
Step-by-step Solution
Detailed explanation
General term of \(\left(2 x^{2}-\frac{1}{x}\right)^{8}\) is \(^{8} \mathrm{C}_{\mathrm{r}}\left(2 \mathrm{x}^{2}\right)^{8-\mathrm{r}}\left(\frac{-1}{\mathrm{x}}\right)^{\mathrm{r}}\) \(\therefore \) Given expression is equal to…
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