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JEE Mains · Maths · STD 11 - 10.1 circle and system of circle

Suppose that two chords, drawn from the point \((1, 2)\) on the circle \(x^2 + y^2 + x - 3y = 0\) are bisected by the \(y\)-axis. If the other ends of these chords are \(R\) and \(S\), and the mid point of the line segment \(RS\) is \((\alpha, \beta)\), then \(6(\alpha + \beta)\) is equal to:

  1. A \(1\)
  2. B \(3\)
  3. C \(4\)
  4. D \(6\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(3\)

Step-by-step Solution

Detailed explanation

Let the other end of the chord be \((x_1, y_1)\). Since the chord is bisected by the \(y\)-axis, the midpoint of the chord lies on the \(y\)-axis. The midpoint of the chord joining \((1, 2)\) and \((x_1, y_1)\) is \(\left(\dfrac{x_1 + 1}{2}, \dfrac{y_1 + 2}{2}\right)\). Since it…
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