JEE Mains · Maths · STD 12 - 6. Application of derivatives
Let \(f(x)=\left|(x-1)\left(x^{2}-2 x-3\right)\right|+x-3, x \in R\). If \(m\) and \(M\) are respectively the number of points of local minimum and local maximum of \(f\) in the interval \((0,4)\), then \(m + M\) is equal to
- A \(5\)
- B \(7\)
- C \(3\)
- D \(12\)
Answer & Solution
Correct Answer
(C) \(3\)
Step-by-step Solution
Detailed explanation
\(f(x)=\left\{\begin{array}{c}\left(x^{2}-1\right)(x-3)+(x-3), x \in(0,1] \cup[3,4) \\ -\left(x^{2}-1\right)(x-3)+(x-3), x \in[1,3]\end{array}\right.\)…
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