JEE Mains · Maths · STD 12 - 13. probability
Four fair dice are thrown independently \(27\) times. Then the expected number of times, at least two dice show up a three or a five, is
- A \(11\)
- B \(12\)
- C \(22\)
- D \(21\)
Answer & Solution
Correct Answer
(A) \(11\)
Step-by-step Solution
Detailed explanation
4 dice are independently thrown. Each die has probability to show 3 or 5 is \(p=\frac{2}{6}=\frac{1}{3}\) \(\therefore \quad q =1-\frac{1}{3}=\frac{2}{3}\) (not showing 3 or \(\left.5\right)\) Experiment is performed with 4 dices independently. \(\therefore\) Their binomial…
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