JEE Mains · Maths · STD 12 - 1. relation and function
If the function \(f\,:\,R - \,\{ 1, - 1\} \to A\) defined by \(f\,(x)\, = \frac{{{x^2}}}{{1 - {x^2}}},\) is surjective, then \(A\) is equal to
- A \(R\, - \,[ - 1,0)\)
- B \(R\, - \,( - 1,0)\)
- C \(R\, - \,\{ - 1\} \)
- D \([0,\infty )\)
Answer & Solution
Correct Answer
(A) \(R\, - \,[ - 1,0)\)
Step-by-step Solution
Detailed explanation
\(y\, = \frac{{{x^2}}}{{1 - {x^2}}}\) Range of \(y : R - [ - 1,0)\) for surjective function, \(A\) must be same as above range.
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