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JEE Mains · Maths · STD 11 - 3. trignometrical ratios,functions and identities

If \(\frac{\cos ^2 48^{\circ}-\sin ^2 12^{\circ}}{\sin ^2 24^{\circ}-\sin ^2 6^{\circ}}=\frac{\alpha+\beta \sqrt{5}}{2}\), where \(\alpha, \beta \in N\), then \(\alpha+\beta\) is equal to ___ .

  1. A 2
  2. B 4
  3. C 6
  4. D 8
Verified Solution

Answer & Solution

Correct Answer

(B) 4

Step-by-step Solution

Detailed explanation

Use \(\sin ( A + B ) \sin ( A + B )=\sin ^2 A-\sin ^2 B\) \(\cos (A+B) \cos (A-B)=\cos ^2 A-\sin ^2 B\)…
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