JEE Mains · Maths · STD 11 - 8. sequence and series
The roots of the quadratic equation \(3 x^2-\mathrm{p} x+\mathrm{q}=0\) are \(10^{\text {th }}\) and \(11^{\text {th }}\) terms of an arithmetic progression with common difference \(\frac{3}{2}\). If the sum of the first 11 terms of this arithmetic progression is 88 , then \(q-2 p\) is equal to \(\qquad\) -.
- A 470
- B 474
- C 478
- D 452
Answer & Solution
Correct Answer
(B) 474
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & S_{11}=\frac{11}{2}(2 a+10 d)=88 \\ & a+5 d=8 \\ & a=8-5 \times \frac{3}{2}=\frac{1}{2} \end{aligned}\) Roots are…
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