JEE Mains · Maths · STD 12 - 9. differential equations
If \(y=y(x)\) is the solution of the differential equation \(\frac{d y}{d x}+\frac{4 x}{\left(x^2-1\right)} y=\frac{x+2}{\left(x^2-1\right)^{\frac{5}{2}}},x > 1\) such that \(y(2)=\frac{2}{9} \log _e(2+\sqrt{3})\) and \(y(\sqrt{2})=\) \(\alpha \log _e(\sqrt{\alpha}+\beta)+\beta-\sqrt{\gamma}, \alpha, \beta, \gamma \in N\), then \(\alpha \beta \gamma\) is equal to \(........\).
- A \(8\)
- B \(6\)
- C \(10\)
- D \(14\)
Answer & Solution
Correct Answer
(B) \(6\)
Step-by-step Solution
Detailed explanation
\(\frac{d y}{d x}+\frac{4 x}{\left(x^2-1\right)} y=\frac{x+2}{\left(x^2-1\right)^{\frac{5}{2}}}, x > 1\) \(\text { I.F. }=e^{\int \frac{4 x}{x^2-1} d x}\) \(\text { I.F. }=\left( x ^2-1\right)^2\)…
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