JEE Mains · Maths · STD 11 - 6. permutation and combination
Two women and some men participated in a chess tournament in which every participant played two games with each of the other participants. If the number of games that the men played between themselves exceeds the number of games that the men played with the women by \(66\), then the number of men who participated in the tournament lies in the interval
- A \([8, 9]\)
- B \([10, 12)\)
- C \((11, 13]\)
- D \((14, 17)\)
Answer & Solution
Correct Answer
(B) \([10, 12)\)
Step-by-step Solution
Detailed explanation
Let no. of men \(=n\) No. of women \(=2\) Total participants \(=n+2\) No. of games that \(M_1\) plays with all pther men \(=2(n-1)\) These games are played by all men \(M_2,M_3,.........M_n.\) So, total no. of games among men \(=n.2(n-1).\) However, we must divide it by \('2',\)…
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