JEE Mains · Maths · STD 11 - 9. straight line
Let the line \(L_1 : x + 3 = 0\) intersect the lines \(L_2 : x - y = 0\) and \(L_3 : 3x + y = 0\) at the points \(A\) and \(B\), respectively. Let the bisector of the obtuse angle between the lines \(L_2\) and \(L_3\) intersect the line \(L_1\) at the point \(C\). Then \(BC^2 : AC^2\) is equal to:
- A \(5:1\)
- B \(1:5\)
- C \(2:3\)
- D \(3:2\)
Answer & Solution
Correct Answer
(A) \(5:1\)
Step-by-step Solution
Detailed explanation
The intersection point of \(L_1: x = -3\) and \(L_2: x - y = 0\) is \(A(-3, -3)\). The intersection point of \(L_1: x = -3\) and \(L_3: 3x + y = 0\) is \(B(-3, 9)\). The lines \(L_2\) and \(L_3\) intersect at the origin \(O(0, 0)\). The distances from the origin to \(A\) and…
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