JEE Mains · Maths · STD 11 - 4.1 complex nubers
For \(z \in C\) if the minimum value of \((|z-3 \sqrt{2}|+|z-p \sqrt{2} i|)\) is \(5 \sqrt{2}\), then a value of \(P\) is \(.......\)
- A \(3\)
- B \(\frac{7}{2}\)
- C \(4\)
- D \(\frac{9}{2}\)
Answer & Solution
Correct Answer
(C) \(4\)
Step-by-step Solution
Detailed explanation
It is sum of distance of \(z\) from \((3 \sqrt{2}, 0)\) and \((0, p \sqrt{2})\) For minimising, \(z\) should lie on \(A B\) and \(A B=5 \sqrt{2}\) \((A B)^{2}=18+2 p^{2}\) \(p=\pm 4\)
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