JEE Mains · Maths · STD 11 - 4.1 complex nubers
Let \(z = 1 + ai\) be a complex number, \(a > 0\), such that \(z^3\) is areal number. Then the sum \(1 + z + z^2 + .... + z^{11}\) is equal to
- A \(1365\sqrt 3 i\)
- B \(-1365\sqrt 3 i\)
- C \(-1250\sqrt 3 i\)
- D \(1250\sqrt 3 i\)
Answer & Solution
Correct Answer
(B) \(-1365\sqrt 3 i\)
Step-by-step Solution
Detailed explanation
\(z=1+a i\) \(z^{2}=1-a^{2}+2 a i\) \(z^{2} \cdot z=\left\{\left(1-a^{2}\right)+2 a i\right\}\{1+a i\}\) \(=\left(1-a^{2}\right)+2 a i+\left(1-a^{2}\right) \quad a i-2 a^{2}\) \(\because \quad z^{3}\) is real \(\Rightarrow 2 a+\left(1-a^{2}\right) a=0\)…
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