JEE Mains · Maths · STD 12 - 11. three dimension geometry
Let the image of the point \(P (2,-1,3)\) in the plane \(x+2 y-z=0\) be \(Q\). Then the distance of the plane \(3 x+2 y+z+29=0\) from the point \(Q\) is \(.........\).
- A \(\frac{22 \sqrt{2}}{7}\)
- B \(\frac{24 \sqrt{2}}{7}\)
- C \(2 \sqrt{14}\)
- D \(3 \sqrt{14}\)
Answer & Solution
Correct Answer
(D) \(3 \sqrt{14}\)
Step-by-step Solution
Detailed explanation
eq. of line \(PM\) \(\frac{x-2}{1}=\frac{y+1}{2}=\frac{z-3}{-1}=\lambda\) any point on line \(=(\lambda+2,2 \lambda-1,-\lambda+3)\) for point ' \(m\) ' \((\lambda+2)+2(2 \lambda-1)-(3-\lambda)=0\) \(\lambda=\frac{1}{2}\) Point…
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