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JEE Mains · Maths · STD 11 - 10.2 parabola,ellipse,hyperbola

Let \(H: \dfrac{x^2}{a^2}-\dfrac{y^2}{b^2}=1\) be a hyperbola such that the distance between its foci is \(6\) and the distance between its directrices is \(\dfrac{8}{3}\). If the line \(x=\alpha\) intersects the hyperbola \(H\) at the points \(A\) and \(B\) such that the area of the triangle \(AOB\) is \(4\sqrt{15}\), where \(O\) is the origin, then \(\alpha^2\) equals

  1. A \(12\)
  2. B \(16\)
  3. C \(24\)
  4. D \(25\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(16\)

Step-by-step Solution

Detailed explanation

Given distance between foci is \(2ae = 6 \Rightarrow ae = 3\) Distance between directrices is \(\dfrac{2a}{e} = \dfrac{8}{3}\) Multiplying the two equations, we get \(4a^2 = 16 \Rightarrow a^2 = 4\) Dividing the two equations, we get \(e^2 = \dfrac{9}{4}\) Using…
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