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JEE Mains · Maths · STD 12 - 1. relation and function

The function \(f: R-\)\(>R,\) \(f(x)=\frac{x^2+2 x-15}{x^2-4 x+9}, x \in R\) is

  1. A  both one-one and onto.
  2. B onto but not one-one.
  3. C neither one-one nor onto.
  4. D  one-one but not onto.
Verified Solution

Answer & Solution

Correct Answer

(C) neither one-one nor onto.

Step-by-step Solution

Detailed explanation

\(f(x)=\frac{(x+5)(x-3)}{x^2-4 x+9}\) Let \(g(x)=x^2-4 x+9\) \( D < 0 \) \( g(x) > 0\) for \(x \in R\) \(\therefore\left[\begin{array}{l}\mathrm{f}(-5)=0 \\ \mathrm{f}(3)=0\end{array}\right.\) So, \(\mathrm{f}(\mathrm{x})\) is many-one. again, \( y x^2-4 x y+9 y=x^2+2 x-15 \)…
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