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JEE Mains · Maths · STD 11 - 14. probability

Let \(X\) be a set containing \(10\) elements and \(P(X)\) be its power set. If \(A\) and \(B\) are picked up at random from \(P(X),\) with replacement, then the probability that \(A\) and \(B\) have equal number elements, is

  1. A \(\frac{{\left( {{2^{10}} - 1} \right)}}{{{2^{10}}}}\)
  2. B \(\frac{{^{20}{C_{10}}}}{{{2^{10}}}}\)
  3. C \(\frac{{\left( {{2^{10}} - 1} \right)}}{{{2^{20}}}}\)
  4. D \(\frac{{^{20}{C_{10}}}}{{{2^{20}}}}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\frac{{^{20}{C_{10}}}}{{{2^{20}}}}\)

Step-by-step Solution

Detailed explanation

Required porbability is \(\frac{{{{\left( {^{10}{C_0}} \right)}^2} + {{\left( {^{10}{C_1}} \right)}^2} + {{\left( {^{10}{C_2}} \right)}^2} + ...... + {{\left( {^{10}{C_{10}}} \right)}^2}}}{{{2^{10}}}}\) \( = \frac{{{\,^{20}}{C_{10}}}}{{{2^{20}}}}\)
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