JEE Mains · Maths · STD 12 - 8. Application and integration
Let the area of the region \(\{(x, y): x-2 y+4 \geq 0\), \(\left.x+2 y^2 \geq 0, x+4 y^2 \leq 8, y \geq 0\right\}\) be \(\frac{m}{n}\), where \(m\) and \(\mathrm{n}\) are coprime numbers. Then \(\mathrm{m}+\mathrm{n}\) is equal to
- A \(465\)
- B \(145\)
- C \(259\)
- D \(119\)
Answer & Solution
Correct Answer
(D) \(119\)
Step-by-step Solution
Detailed explanation
\(A=\int_0^1\left[\left(8-4 y^2\right)-\left(-2 y^2\right)\right] \mathrm{dy}+ \int_1^{3 / 2}\left[\left(8-4 y^2\right)-(2 y-4)\right] \mathrm{dy}\)…
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