JEE Mains · Maths · STD 11 - 3. trignometrical ratios,functions and identities
Let \(P = \{\theta \in [0, 4\pi] : \tan^2\theta \neq 1\}\) and \(S = \{a \in \mathbb{Z} : 2(\cos^8\theta - \sin^8\theta)\sec 2\theta = a^2, \theta \in P\}\). Then \(n(S)\) is:
- A \(0\)
- B \(1\)
- C \(2\)
- D \(3\)
Answer & Solution
Correct Answer
(A) \(0\)
Step-by-step Solution
Detailed explanation
Given the expression \(2(\cos^8\theta - \sin^8\theta)\sec 2\theta = a^2\). We can simplify the term \(\cos^8\theta - \sin^8\theta\) as follows: \(\cos^8\theta - \sin^8\theta = (\cos^4\theta - \sin^4\theta)(\cos^4\theta + \sin^4\theta)\)…
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