JEE Mains · Maths · STD 11 - 12. limits
\(\lim _{n \rightarrow \infty} \tan \left\{\sum_{r=1}^{n} \tan ^{-1}\left(\frac{1}{1+r+r^{2}}\right)\right\}\) is equal to..........
- A \(1\)
- B \(2\)
- C \(3\)
- D \(4\)
Answer & Solution
Correct Answer
(A) \(1\)
Step-by-step Solution
Detailed explanation
\(\lim _{n \rightarrow a} \tan \left(\sum_{r=1}^{n} \tan ^{-1}\left(\frac{1}{1+r(r+1)}\right)\right)\) \(=\lim _{n \rightarrow a} \tan \left(\sum_{r=1}^{n} \tan ^{-1}\left(\frac{r+1-r}{1+r(r+1)}\right)\right)\)…
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