JEE Mains · Maths · STD 11 - 10.2 parabola,ellipse,hyperbola
Let one end of a focal chord of the parabola \( y^{2}=16x \) be (16, 16). If \( P(\alpha,\beta) \) divides this focal chord internally in the ratio 5 : 2 then the minimum value of \( \alpha+\beta \) is equal to :
- A 22
- B 7
- C 5
- D 16
Answer & Solution
Correct Answer
(B) 7
Step-by-step Solution
Detailed explanation
\( y^{2}=16x \) \(\therefore\) parameter of point A is \( t=2 \) Parameter of point B is \( t=-\frac{1}{2} \) \(\Rightarrow\) Coordinates of \(B\) is \((1, -4)\) Case 1 : \(\alpha=\frac{5+32}{7}=\frac{37}{7} \) \( \beta=\frac{-20+32}{7}=\frac{12}{7} \)…
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