JEE Mains · Maths · STD 12 - 13. probability
Bag \(B_1\) contains 6 white and 4 blue balls, Bag \(B_2\) contains 4 white and 6 blue balls, and Bag \(B_3\) contains 5 white and 5 blue balls. One of the bags is selected at random and a ball is drawn from it. If the ball is white, then the probability, that the ball is drawn from Bag \(B_2\), is :
- A \(\frac{4}{15}\)
- B \(\frac{1}{3}\)
- C \(\frac{2}{5}\)
- D \(\frac{2}{3}\)
Answer & Solution
Correct Answer
(A) \(\frac{4}{15}\)
Step-by-step Solution
Detailed explanation
\(E_1: B a g B_1\) is selected \(\begin{array}{lll} B_1 & B_2 & B_3 \\ \text { 6W4B } & 4 \mathrm{~W} 6 \mathrm{~B} & 5 \mathrm{~W} 5 \mathrm{~B} \end{array}\) \(\mathrm{E}_2:\) bag \(\mathrm{B}_2\) is selected \(E_3: B a g B_3\) is selected A : Drawn ball is white We have to…
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