JEE Mains · Maths · STD 11 - 14. probability
Five numbers \(x _{1}, x _{2}, x _{3}, x _{4}, x _{5}\) are randomly selected from the numbers \(1,2,3, \ldots \ldots, 18\) and are arranged in the increasing order \(\left( x _{1}< x _{2}< x _{3}< x _{4}< x _{5}\right)\). The probability that \(x_{2}=7\) and \(x_{4}=11\) is
- A \(\frac{1}{136}\)
- B \(\frac{1}{68}\)
- C \(\frac{1}{72}\)
- D \(\frac{1}{34}\)
Answer & Solution
Correct Answer
(B) \(\frac{1}{68}\)
Step-by-step Solution
Detailed explanation
No. of ways to select and arrange \(x _{1}, x _{2}, x _{3}, x _{4}, x _{5}\) from \(1,2,3 \ldots \ldots \ldots \ldots \ldots . \ldots18\) \(n ( s )={ }^{18} C _{5}\) \(x_{1}\left (x_{2}\right) \quad x_{3} \quad\left(x_{4}\right)\quad x_{5}\) \(7\) \(11\)…
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