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JEE Mains · Maths · STD 12 - 6. Application of derivatives

Let \(M\)  and  \(m\)  be respectively the local maximum and the local minimum values of the function, \(f(x) = \,2{x^3} - 9{x^2} + 12x + 5\)  in the interval \([0, 3].\)  Then \(M-m\)  is equal to

  1. A \(1\)
  2. B \(5\)
  3. C \(4\)
  4. D \(9\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(1\)

Step-by-step Solution

Detailed explanation

Here, \(f(x)=2 x^{3}-9 x^{2}+12 x+5\) \(\Rightarrow f^{\prime}(x)=6 x^{2}-18 x+12=0\) For maxima or minima put \(f^{\prime}(x)=0\) \(\Rightarrow x^{2}-3 x+2=0\) \(\Rightarrow x=1\) or \(x=2\) Now, \(f^{\prime \prime}(x)=12 x-18\)…
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