JEE Mains · Maths · STD 11 - 8. sequence and series
Let \(a, b, c, d\) and \(p\) be any non zero distinct real numbers such that \(\left(a^{2}+b^{2}+c^{2}\right) p^{2}-2(a b+b c+ cd ) p +\left( b ^{2}+ c ^{2}+ d ^{2}\right)=0 .\) Then
- A \(a,c,p\) are in \(G.P.\)
- B \(a,c,p\) are in \(A.P.\)
- C \(a,b,c,d\) are in \(G.P.\)
- D \(a,b,c,d\) are in \(A.P.\)
Answer & Solution
Correct Answer
(C) \(a,b,c,d\) are in \(G.P.\)
Step-by-step Solution
Detailed explanation
\(\left(a^{2}+b^{2}+c^{2}\right) p^{2}+2(a b+b c+c d) p+b^{2}+c^{2}+d^{2}\) \(=0\) \(\Rightarrow\left(a^{2} p^{2}+2 a b p+b^{2}\right)+\left(b^{2} p^{2}+2 b c p+c^{2}\right)+\) \(\left(c^{2} p^{2}+2 c d p+d^{2}\right)=0\) \(\Rightarrow(a b+b)^{2}+(b p+c)^{2}+(c p+d)^{2}=0\) This…
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