JEE Mains · Maths · STD 12 - 8. Application and integration
The area (in square units) bounded by the curves \(y = \sqrt x \) and \(2y - x + 3 = 0\) and \(X-\) axis and lying in the first quadrant is :
- A \(9\)
- B \(36\)
- C \(18\)
- D \(\frac{{27}}{4}\)
Answer & Solution
Correct Answer
(A) \(9\)
Step-by-step Solution
Detailed explanation
\(y = \sqrt x \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,....\left( 1 \right)\) \({\rm{ and }}\quad 2y - x + 3 = 0\,\,\,\,\,\,\,\,\,\,.....\left( 2 \right)\) On solving both \(y=-1,3\) Required area \( = \int\limits_0^3 {\left\{ {(2y + 3) - {y^2}} \right\}dy} \)…
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