JEE Mains · Maths · STD 11 - 6. permutation and combination
All possible numbers are formed using the digits \(1, 1, 2, 2, 2, 2, 3, 4, 4\) taken all at a time. The number of such numbers in which the odd digits occupy even places is
- A \(180\)
- B \(175\)
- C \(162\)
- D \(160\)
Answer & Solution
Correct Answer
(A) \(180\)
Step-by-step Solution
Detailed explanation
Number of such numbers \({ = ^4}{C_3} \times \frac{{3!}}{{2!}} \times \frac{{6!}}{{2!4!}} = 180\)
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